Modern C++

C++: Check if const Objects Are the Same at Compile-Time

Tired of runtime errors? Learn how to leverage C++ `constexpr` and `consteval` to check if const objects are identical at compile-time, boosting performance and safety.

A

Adrian Volkov

A C++ enthusiast and software architect specializing in performance optimization and metaprogramming.

7 min read10 views

Ever found yourself staring at two `const` global objects, wondering if you could just know they were identical before your program even starts? It’s a common scenario in systems programming, embedded development, and high-performance computing. Relying on runtime checks works, but it feels... inefficient. What if you could shift that validation left, directly into the compiler?

Good news: Modern C++ gives you the tools to do exactly that. Let's dive into how you can verify object equality at compile-time, catching potential mismatches and unlocking powerful new design patterns.

The Problem: Why Compare Objects at Compile-Time?

Comparing objects at compile-time isn't just an academic exercise. It has tangible benefits:

  • Ironclad Safety: You can use static_assert to guarantee that certain configurations or constants are identical. If they're not, the code simply won't compile. This eliminates a whole class of runtime configuration errors.
  • Zero-Cost Abstractions: The comparison happens entirely during compilation. There is no runtime CPU cycle spent on the check, making it a true zero-cost abstraction.
  • Enhanced Metaprogramming: It enables more advanced template metaprogramming, where the equality of two constant objects can determine which template specialization is chosen.

Imagine you have two configuration objects for a hardware peripheral, and you need to ensure they are configured identically before generating code for them. A compile-time check is the perfect tool for this job.

The Classic Limitation: A Standard operator== Won't Cut It

Your first instinct might be to just use the equality operator (==) inside a static_assert. Let's try it with a simple struct:


struct Color {
  unsigned char r, g, b;

  // A standard, runtime operator==
  bool operator==(const Color& other) const {
    return r == other.r && g == other.g && b == other.b;
  }
};

const Color RED = {255, 0, 0};
const Color ALSO_RED = {255, 0, 0};

// static_assert(RED == ALSO_RED, "Colors must be the same!"); // ❌ Compilation Error!

This fails to compile. Why? Because a standard operator== is a function that executes at runtime. A static_assert, on the other hand, needs a constant expression—something the compiler can evaluate on its own, without running the program. The compiler sees a call to a runtime function and can't resolve its value.

Enter constexpr: The Compile-Time Game Changer

Since C++11, the constexpr specifier has been our primary tool for compile-time computation. When you declare a function as constexpr, you're telling the compiler: "If this function is called with arguments that are known at compile-time, you can (and should) evaluate it right now."

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This is the key. By making our operator== a constexpr function, we give the compiler permission to run it during compilation.

Building a Compile-Time Equality Checker: A Practical Example

Let's refactor our Color struct. The changes are minimal but incredibly powerful.

First, we need to ensure our type can be used in a constant expression. For a class type, this means it must be a "Literal Type". The rules are a bit detailed, but for a simple struct like ours, it's automatic as long as it has a constexpr constructor and all its non-static data members are public.

Since C++14, the rules for constexpr functions are much more relaxed, allowing for local variables, loops, and more. In C++20, it's even more powerful. For our purpose, the change is simple:


#include <cstdint>

struct Color {
  std::uint8_t r, g, b;

  // The magic ingredient: constexpr!
  constexpr bool operator==(const Color& other) const {
    return r == other.r && g == other.g && b == other.b;
  }
};

// Use constexpr for the objects to guarantee they are compile-time constants.
constexpr Color RED = {255, 0, 0};
constexpr Color ALSO_RED = {255, 0, 0};
constexpr Color BLUE = {0, 0, 255};

// Now this works!
static_assert(RED == ALSO_RED, "Red colors should be identical.");

// And this will correctly fail compilation, as intended.
// static_assert(RED == BLUE, "Red and Blue should not be identical.");

Success! The static_assert now compiles because the compiler can invoke the constexpr operator== with the constexpr objects RED and ALSO_RED, evaluate the result to true, and satisfy the assertion.

Handling More Complex Types

What about types that aren't as simple as Color? The main restriction for compile-time constants is that they cannot involve dynamic memory allocation in a way that persists past the constant evaluation.

This means types like std::string and std::vector, which use the heap, are generally off-limits for the members of your constexpr objects.

However, you can use their compile-time-friendly counterparts:

  • Instead of std::string, use std::string_view (since C++17).
  • Instead of std::vector, use std::array.

Let's look at a configuration struct using these types:


#include <string_view>
#include <array>
#include <algorithm> // for std::equal

struct DeviceConfig {
    std::string_view name;
    std::array<int, 4> pin_layout;

    constexpr bool operator==(const DeviceConfig& other) const {
        // std::string_view's operator== is already constexpr!
        // For std::array, we can use std::equal or a simple loop.
        return name == other.name && 
               std::equal(pin_layout.begin(), pin_layout.end(), other.pin_layout.begin());
    }
};

constexpr DeviceConfig SENSOR_A_CONFIG = {"temp_sensor", {1, 2, 3, 4}};
constexpr DeviceConfig SENSOR_A_DUPLICATE = {"temp_sensor", {1, 2, 3, 4}};
constexpr DeviceConfig SENSOR_B_CONFIG = {"humidity_sensor", {5, 6, 7, 8}};

static_assert(SENSOR_A_CONFIG == SENSOR_A_DUPLICATE, "Sensor A configs must match.");

Notice that std::string_view::operator== is already constexpr since C++17, and algorithms like std::equal are constexpr since C++20, making this kind of complex comparison increasingly straightforward.

C++20 and Beyond: consteval and std::is_constant_evaluated()

C++20 supercharged our compile-time capabilities with two new features:

  1. consteval (Immediate Functions): If you mark a function as consteval instead of constexpr, you are guaranteeing that it must produce a compile-time constant. It can only be called during constant evaluation. This is a stronger contract than constexpr and can be useful for utility functions that only make sense at compile-time.
  2. std::is_constant_evaluated(): This magical function returns true if it's being evaluated within a compile-time context and false otherwise. It lets you write a single constexpr function that can have different logic for compile-time and runtime execution. For instance, you could use a simple, efficient algorithm at compile-time and a more complex, optimized (e.g., SIMD) version at runtime.

// A function that MUST run at compile time.
consteval bool are_equal_immediate(const Color& c1, const Color& c2) {
    return c1 == c2;
}

// This is fine
static_assert(are_equal_immediate(RED, ALSO_RED));

// This would fail to compile because the call can't be evaluated at compile-time
// Color c1 = {1,1,1};
// bool result = are_equal_immediate(c1, RED); // ❌ Error!

Runtime vs. Compile-Time Checks: A Quick Comparison

To summarize the differences, here’s a handy table:

Feature Runtime Check Compile-Time Check
When it Executes During program execution During compilation
Error Detection When the line of code is hit, possibly in production Before the program is ever created; prevents bad builds
Performance Cost Has a CPU cost (usually small, but non-zero) Zero runtime cost; may increase compile times slightly
Applicable Data Any data, including user input and dynamic values Only `const`/`constexpr` data known at compile-time
Key C++ Features if, assert(), standard operator== static_assert, constexpr, consteval

Key Takeaways

Shifting correctness checks to the compiler is a hallmark of modern C++ development. For comparing const objects:

  • Make your equality operator constexpr. This is the fundamental step that allows the compiler to perform the comparison.
  • Ensure your objects are `constexpr`. The inputs to a compile-time evaluation must themselves be compile-time constants.
  • Use compile-time friendly types like std::array and std::string_view for non-trivial members to avoid issues with dynamic memory.
  • Use static_assert to enforce equality. This provides a hard guarantee that if the code compiles, the condition is met.
  • Explore C++20's consteval for functions that should only ever run at compile-time.

By embracing these features, you can write code that is not only faster but also significantly safer and more robust, catching a whole class of bugs before they ever reach a user.

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